SEBA Class 6 Mathematics Chapter 14 Practical Geometry Solutions, SEBA Class 6 Maths Notes in English Medium, SEBA Class 6 Mathematics Chapter 14 Practical Geometry Notes to each chapter is provided in the list so that you can easily browse throughout different chapter Assam Board SEBA Class 6 Mathematics Chapter 14 Practical Geometry Notes and select needs one.
SEBA Class 6 Mathematics Chapter 14 Practical Geometry
Also, you can read the SCERT book online in these sections Solutions by Expert Teachers as per SCERT (CBSE) Book guidelines. SEBA Class 6 General Mathematics Textual Question Answer. These solutions are part of SCERT All Subject Solutions. Here we have given SEBA Class 6 Mathematics Chapter 14 Practical Geometry Solutions for All Subject, You can practice these here.
Practical Geometry
Chapter – 14
| Exercise – 14 (A) |
1. Draw a line segment of length given below.
(i) 4.5 cm
Ans: 4.5 cm
(ii) 11.3 cm
Ans: 11.3 cm
2. Draw a circle of the following radius.
(i) 7 cm
Ans: 7 cm
(ii) 6.7 cm
Ans: 6.7 cm
3. Draw a line segment of length 6 cm. Take a point C at a distance 3.5 cm from A. Now construct a perpendicular to AB at C.
Ans:
Step 1: A line segment AB = 6 cm is drawn. A point C at a distance 3.5 cm from A is taken.
Step 2: With C as centre and a convenient radius, construct a part circle (arc)
Step 3: With P and Q as centres and a radius greater than PC, construct two arcs which cut each other at R.
4. Draw a line segment of length 8 cm. Take any point not on the line segment. Construct a perpendicular to the line segment from this external point.
Ans:
Let P be the point out-side the line AB (8cm) from which it is required to draw perpendicular to l.
Step1: With centre P draw an arc which cuts I at two points. Let the arc cut the line I at the point A and B.
Step 2: With A as centre and radius greater than half of AB draw an arc opposite to P, With B as centre and with same radius draw an arc to cut the previous arc at a point say Q.
Step3: Join P and Q. PQ is the perpendicular drawn from P to the line l.
5. Draw a line segment of length 7.2 cm. Draw two perpendiculars at the end points of the line segment (If necessary extend the line segment at both ends)
Ans: A line segment PQ of length 7.2 cm is drawn. It is required to draw two perpendiculars at the end points of the line PQ.
With two centres P and Q two arcs are drawn. These two arcs cut the line segment at E and F. Now, with centres E and F two arcs are drawn with same radius. These arcs cuts the former arcs at the two points at R and A. Again, taking same radius two arcs are drawn. To arcs cut the farmer arcs at S and B points.
Again, taking S and B as centres with same radius two arcs are drawn. These two arcs cut at T and C. T, P and C, Q are joined. TP and CQ are two perpendiculars at the end points of the line segment.
6. Draw a line segment of length 5.6 cm and bisect it.
Ans:
Let AB = 5.6 cm is drawn by a scale and it is required to bisect.
Step1: With A as centre and radius greater than half of AB is drawn an arc.
Step2: With B as centre and with the same radius is drawn another arc. This arc cuts the former arc at two points P and Q.
Step3: Join P and Q PQ is the perpendicular bisector of the line segment AB Measuring with a scale, it is seen that AC = BC = 2.8cm
7. Draw a line segment of length AB. Construct the perpendicular bisector of AB. Take any point C on the perpendicular bisector. Examine if AB = AC.
Ans:
Ans: Step1: With A as centre and radius greater than half of AB is drawn an arc.
Step2: With B as centre and with the same radius is drawn another arc. This arc cuts the former arc at two points P and Q.
Join P and Q PQ is the perpendicular bisector of the line segment AB Measuring with a scale, it is seen that AC = BC = 3cm
Now, with a scale, it is measured and found that AC = 3 cm and CB = 3 cm.
∴ AB = AC = 3 cm [Examined]
8. Draw a circle of radius 5 cm. Draw any chord of the circle. Construct the per-pendicular bisector of the chord. Does the perpendicular bisector pass throught the centre of the circle?
Ans:
Steps of Construction:
Step 1: Draw a point with a sharp pencil and markit at C.
Step 2: Open the compass for the required radius 5 cm. by putting the pointer on O and opening the pencil upto 5 cm.
Step 3: Place the pointer of the compass at C.
Step 4: Turn the compass slowly to draw the circle.
Step7: With the same radius and with B as centre, draw another circle using compass. Let it cut the previous circle at D and E.
Q.9. Draw a circle of radius 4 cm. Draw any two chords of the circle AB and CD such that AB is not parallel to CD. Draw the perpendicular bisectors to AB and CD. Do the perpendicular bisectors intersect at O.
Ans:
Steps of Construction:
Step1: Draw a point with a sharp pencil and mark it as O.
Step 2: Open the compasses for the required radius 4 cm. by putting the pointer on O and opening the pencil upto 4 cm.
Step 3: Place the pointer of the compass at O.
Step 4: Turn the compass slowly to draw the circle.
Step7: With the same radius and with B as centre, draw another two arcs using compass. Let it cut the previous circle at E and F.
| Exercise – 14 (B) |
1. With the help of a protractor draw an angle of given measure.
(i) 30°
Ans:
(ii) 50°
Ans: 50°
(iii) 47°
Ans:
(iv) 85°
Ans:
(v) 97°
Ans: 97°
(vi) 130°
Ans: 130°
(vii) 160°
Ans: 160°
2. Draw an angle of any measure. Using scale and compass construct an angle equal to it.
Ans:
Suppose ∠ABC is the given angle, we do not know that measure of this angle. Now, we have to construct an angle equal to ∠ABC.
Step-1: Draw any line I and take a point P on it.
Step 2: With B as centre and with any radius draw an arc. The arc cuts BA and BC at D and E respectively.
Step 3: With P as centre and with former radius draw an arc. This are cuts the line at R.
Step 4: Taking R as centre, draw an arc with radius DE. This arc cuts the previous arc (Step-3) at Q.
Step 5: The angle ∠QPR is the required angle equal to ∠ABC.
3. Draw an angle and construct the bisector of the angle.
Ans: Suppose ∠ABC is the given angle. It is required to divide the angle equally into two halves, that means we are to construct the bisector of the angle.
Step 1: With B as centre draw an arc with any radius. Let the arc cut BA and BC at D and E respectively.
Step 2: With D and E as centre draw two arcs with equal radius (the radius is more than half of DE). Let the two arcs cut at a point P.
Step 3: Join BP. BP is the bisector of the angle ∠ABC.
Q.4. Draw a 700 angle with the protractor. Now bisect the angle with a compass.
Ans:
Let an angle ∠ABC = 70° It is required to bisect the given angle.
Step1: Draw a line segment AB of any length. Place the centre of the protractor at A and the horizontal edge along AB. Find 70 mark in the protractor Look at the scale which has 0″ mark near AB). Mark a point at 70°.
Step 2: Join AC ∠BAC is required angle 700.
Step 3: With A as centre Draw an arc with any radius. Let the arc cut AB and AC at AC and AB at D and E respectively.
Step 4: With D and E as centre draw two arcs with equal radius (the radius is more than half of DE) Let the two arcs cut a point P.
Step 5: Jion AP.
AP is the bisector of the angle ∠BAC
∴ ∠BAP = ∠CAP = 350
5. Without using protractor construct an angle of each measure given below.
(i) 60°
Ans: 60°
∠ABC = 60°
(ii) 30°
Ans:
∠PQR = 30°
(iii) 15°
Ans:
∠MON = 15°
(iv) 90°
Ans:
∠ABC = 90°
(v) 120°
Ans:
∠MON = 120°
(vi) 45°
Ans:
∠POQ = 45°
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