SEBA Class 6 Mathematics Chapter 11 Decimal Fractions

SEBA Class 6 Mathematics Chapter 11 Decimal Fractions Solutions, SEBA Class 6 Maths Notes in English Medium, SEBA Class 6 Mathematics Chapter 11 Decimal Fractions Notes to each chapter is provided in the list so that you can easily browse throughout different chapter Assam Board SEBA Class 6 Mathematics Chapter 11 Decimal Fractions Notes and select needs one.

SEBA Class 6 Mathematics Chapter 11 Decimal Fractions

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Also, you can read the SCERT book online in these sections Solutions by Expert Teachers as per SCERT (CBSE) Book guidelines. SEBA Class 6 General Mathematics Textual Question Answer. These solutions are part of SCERT All Subject Solutions. Here we have given SEBA Class 6 Mathematics Chapter 11 Decimal Fractions Solutions for All Subject, You can practice these here.

Decimal Fractions

Chapter – 11

1. Write as decimals-

(i) 25 thousandths.

Ans: 25 thousandths

= 25/1000

= 0.025

(ii) 13 ten thousandths.

Ans: 13 ten thousandths

= 13/10000

= 0.0013

(iii) 3059 ten thousandths.

Ans: 3059 ten thousandths

= 3059/10000

= 0.3059

2. Express using decimal point-

(i) 6/1000

Ans: 6/1000 = 0.006

(ii) 25/1000

Ans: 25/1000 = 0.025

(iii) 3/100

Ans: 3/100 = 0.03

(iv) 105/10000

Ans: 105/10000 = 0.03 = 0.0105

3. Express 4631.219 in expanded from-

Ans: The expanded form of 4631.219 is:

4000 + 600 + 30 + 1 + 0.2 + 00.1 + 0.009

Place value: (4 × 1000) + (6 × 100) + (3 × 10) + (1 × 1) + (2 × 0.1) + (1 × 0.01) + ( 9 × 0.001)

4. Find the place value of the following expanded decimal numbers and write in expanded from.

(i) 543.28

Ans: Place value of 5 = 5 hundreds = 5 × 100 = 500 

Place value of 4 = 4 tens = 4 × 10 = 40 

Place value of 3 = 3 ones = 3 × 1 = 3 

Place value of 2 = 2 tenths = 2/10 = 0.2

Place value of 8 = 8 hundredths = 8/100 = 0.8 

∴ Expanded form of 543.28 = 500 + 40 + 3 + 0.2 + 0.8

(ii) 4275.198

Ans: Place value of 4 = 4 thousands = 4 × 1000 = 4000 

Place value of 2 = 2 hundreds = 2 × 100 = 200 

Place value of 7 = 7 tens = 7 × 10 = 70 

Place value of 5 = 5 ones = 5 × 1 = 5

Place value of l = 1 tenths = 1/10 = 0.1

Place value of 9 = 9 hundredths = 9/100 = 0.09

Place value of 8 = 8 thousandths = 8/1000 = 0.008 

∴ The expanded form of 4275.198 = 4000 + 200 + 70 + 5 + 0.1 + 0.9 + 0.008

1. Express the following decimal numbers as ordinary fractions.

(a) 4.3

Ans: 4.3

(b) 0.01

Ans: 0.01

= 1/100

(c) 1.1

Ans: 1.1

(d) 60.01

Ans: 60.01

(e) 4.0108

Ans: 4.0108

2. Express the following in decimal-

(a) Nine tenth.

Ans: Nine tenth

= 9/10

= 0.9

(b) Five tens and seven tenths.

Ans: Five tens and seven tenths

= 50 + 7/10

= 50.7

(c) Eight tens, three ones and four tenths.

Ans: Eight tens, three ones and four tenths

= 80 + 3 + 4/10

= 83.4

(d) Five hundredths.

Ans: Five hundredths

= 5/100

= 0.05

3. Write the following in numbers.

(a) zero decimal point one two five.

Ans: Zero decimal point one two five.

= 0.125

(b) Five decimal point four.

Ans: Five decimal point four.

= 5.4

(c) Seven decimal point zero three.

Ans: Seven decimal point zero three.

= 7.03

(d) Twenty three decimal point three five.

Ans: Twenty three decimal point three five.

= 23.35

4. Write the following decimals in words.

(a) 1.05

Ans: 1.05 = one decimal point zero five.

(b) 0.003

Ans: 0.003 = zero decimal point zero zero three.

(c) 2175.439

Ans: Two thousand one hundred seventy five decimal point four three nine.

5. Write the decimal numbers in the place value table.

(a) 0.71

Ans: 0.71

(b) 12.03

Ans: 12.03

(c) 0.0101

Ans: 0.0101

6. Write the following in expanded from-

(a) 0.05

Ans: 

(b) 31.79

Ans: 

(c) 144.695

Ans: 

7. Express the following in decimals.

(a) 3/10

Ans: 3/10

= 0.3

(b) 3/100

Ans: 3/100

= 0.03

Ans: = 4 + 0.9

= 4.9

Ans: = 653 + 0.2 + 0.03

= 653.23

8. Express the following in decimal-

(a) 1/2

Ans: 

(b) 3/4

Ans: 

(c) 3/50

Ans: 

(d) 7/40

Ans: 

9. Express the following ordinary fractions in decimals-

Ans: 

(b) 9/25

Ans: 

Ans: 

Ans:  

10. Express the following in the lowest from-

(a) 0.8

Ans: 0.8

(b) 1.5

Ans: 1.5

(c) 31.25

Ans: 31.25

(d) 6.001

Ans: 6.001

= 60001/1000

11. Fill in the blanks (use decimal point)

(a) 45 mm = _____________ cm

Ans: 4.5 cm

(b) 1 mm = ______________ m

Ans: 0.01 m

(e) 500 cm = _____________ m

Ans: 5 m

12. Between which two whole numbers on the number line do the following numbers lie and which of these whole numbers in nearer to the number?

(a) 6.9

Ans: → 6.9 is lies between 6 and 7 on the number line but is nearer the number 7.

(b) 25.07

Ans: → 25.07 is lies between 25 and 26 on the number line but is nearer the number 25.

13. Show on the number line-

(a) 0.6

Ans: 0.6

(b) 5.9

Ans: 5.9

1. For each pair of numbers which is the larger number-

(i) 0.849,0.819

Ans: 0.849 > 0.819

(ii) 3.614, 3.616

Ans: 3.614 < 3.616

(iii) 120.5, 120.05

Ans: 120.5 > 120.05

2. Write true or false of the following.

(i) 42.5 = 42.50

Ans: True.

(ii) 361.05 < 361.005

Ans: False.

(iii) 2.43 < 24.3

Ans: True.

3. Arrange in ascending order–

(i) 15.73, 157.3, 1.573, 1573

Ans: 1.573 < 15.73 < 157.3 < 1573

(ii) 0.005, 0.05, 0.0005, 0.5

Ans: 0.0005 < 0.005 < 0.05 < 0.5

4. Arrange the following in descending order –

(a) 67.54, 67.45, 76.54, 67.054, 67.55

Ans: 76.54 > 67.55 > 67.54 > 67.45 > 67.054

(b) 143.63, 243.63, 234.36, 134.41, 143.633

Ans: 243.63 > 234.36 > 143.633 > 143.63 >134.41

5. Using decimal point express the following-

(a) As rupees:

(i) 15 paise.

Ans: 15 paise = 15/100 = Rupees 0.15 Rupees.

(ii) 70 paise.

Ans: 70 paise = 70/100 Rupees 0.70 Rupees.

(iii) 675 paise.

Ans: 675 paise = 6 Rupees + 75 paise.

= 6 Rupees + 75/100 = 6.75 Rupees.

(b) As meter:

(i) 35 cm

Ans: 35 cm = 35/100 = 0.35 m

(ii) 7 m 70 cm

Ans: 7 m 70 cm = 7 + 70 cm

= 7m + 70/100m = 7m + 0.7m = 7.7m

(iii) 305 cm

Ans: 305 cm = 3.05 m

(c) As kilometer:

(i) 5 m

Ans: 5 m = 5/1000 k.m = 0.005 k.m.

(ii) 500 m

Ans: 500 m = 500/1000 k.m = 0.500 k.m

(iii) 7005 m

Ans: 7005 m = 7005/1000 k.m = 7.005 k.m

(d) As kilogram

(i) 15 gram

Ans: 15 gram = 15/1000 k.g = 0.015 k.g 

(ii) 550 gram

Ans: 550 gram = 550/1000 k.g = 0.550 k.g

(iii) 5725 gram

Ans: 5725 gram = 5725/1000 k.g = 5.725 k.g 

6. Put a tick (√) in correct answers and (×) in wrong answers. Correct the wrong statements.

(i) 1 mm = 0.1 cm

Ans: √

(ii) 800 m = 0.8 km

Ans: √

(iii) 2785 cm = 27.85 m

Ans: √

(iv) 1 milligram = 1/1000 gram = 0.001 gram

Ans: √

(v) 1 ml = 0.001 litre

Ans: √

1. Find the sum-

(a) 0.506 + 0.03 + 3.14 + 56.198

Ans: 0.506 + 0.03 + 3.14 + 56.198 = 59.874

(b) 37.31 + 405.85 + 10.0015 + 9.9

Ans: 37.31 + 405.85 + 10.0015 + 9.9 = 463.0615

2. (a) Arrange the following numbers in ascending order and find the sum-

94.5, 69.59, 427.001, 3.42, 0.05

Ans: 0.05 < 3.42 < 69.59 < 94.5 < 427.001

Sum = 594.561

(b) Arrange the following numbers in descending order and find the sum-

146.23, 50.64, 426.53, 6.09, 78.35

Ans: 426.53 > 146.23 > 78.35 > 50.64 > 6.09

Sum = 707.84

3. Subtract the following-

(a) 89.005 from 370.69

Ans: 

(b) 0.008 from 6.01

Ans: 

4. The three friends Meera, Anima and Rahima checked their weight in a weighing machine. They weighed 36.145kg, 35.916 kg and 38.016 kg respectively. What is their total weight?

Ans: Weight of Merra = 36.145 kg 

Weight of Anima = 35.916 kg 

and Weight of Rahima = 38.016 kg

∴ Total Weight = 110.077 kg 

∴ Their total Weight = 110.077 kg.

5. Pratap bought four books from the book fair. The price of the books were ₹175.25 and ₹205.50, ₹400 and ₹213.60 respectively. How much money Pratap spent for the books?

Ans: The price of the books were Rs. 175.25,  Rs 205.50 Rs 400 and Rs 213.60

∴ The price of four books =

∴ pratap spent for the books = Rs. 994.35

6. Mojammil went on an outing with his parents during his holidays. They went 4.575km by rickshaw, 425.5 km by rail and 25.425 km by bus. What is the total distance they travelled?

Ans: They went 4.575 km by rickshaw, 425.5 km by rail and 25.425 km by bus,

∴ The total distance = 4.575 km + 425.500 km + 25.425 km = 45.500 km

∴ The total distance they travelled = 455.5 km. 

7. A milkman had 17 litre 790 mililitre of milk in his milk can. He sold 2.750 litre of milk to one person and 5 litre 375 mililitre milk to another person. How much milk is left in the milk can?

Ans: A milkman had 17 litre 790 millilitre of milk in his can.

He sold 2.750 litre + 5.375 millilitre of milk 

2.750 litre + 5.375 litre + 8.125 litre

∴ Milk is left in the milk can = 17.790 litre

-8.125 litre

∴ 9.665 litre of milk is left in the milk can.

8. The difference of two numbers is 213.79. If the larger of the two numbers is 749.53, what is the smaller number?

Ans: The difference of two numbers = 213.79 

The larger number = 749.53 

∴ The smaller number = 749.53 – 213.79 = 535.74 

∴ The smaller number = 535.74

9. Simplify:

(a) 401.55 – 31.21 – 47 . 6 – 135 . 73

Ans: 370.34 -183.33

= 187.01

(b) 19.6 + 71.43 + 66.76 – 92.3

Ans: 19.6 + 71.43 + 66.76 – 92.3 

= 157.79 – 92.3 = 65.49

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