SEBA Class 10 Mathematics Chapter 11 Constructions Solutions, SEBA Class 10 Maths Textbook Notes in English Medium, SEBA Class 10 Mathematics Chapter 11 Constructions Notes in English to each chapter is provided in the list so that you can easily browse throughout different chapter Assam Board SEBA Class 10 Mathematics Chapter 11 Constructions Notes and select needs one.
SEBA Class 10 Mathematics Chapter 11 Constructions
Also, you can read the SCERT book online in these sections Solutions by Expert Teachers as per SCERT (CBSE) Book guidelines. SEBA Class 10 Mathematics Chapter 11 Constructions Question Answer. These solutions are part of SCERT All Subject Solutions. Here we have given SEBA Class 10 Mathematics Chapter 11 Constructions Solutions for All Subject, You can practice these here.
Constructions
Chapter – 11
| Exercise 11.1 |
1: Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts of construction.
Ans:
(i) Take a line segment AB =7.6 cm.
(ii) Draw any ray AX, making an acute angle ∠BAX.
(iii) Locate 5 + 8 = 13 (given ra- tio 5: 8) points A1, A2, A3, A….A12A13 on ray AX such that A1,A2,A3,A4,,A = AA12 A12A13
(iv) Join
(v) Through points A5 C II A13 B making angle equal to くAB 13 A intersecting AB at ‘C’ . The Ac : CB = 5 : 8.
2. Construct a triangle of sides 4cm, 5cm and 6cm and then a triangle 2/ 3 similar to it whose sides are of the corresponding sides of the first 3 triangle.
Ans:
3. Construct a triangle with sides 5cm, 6 cm and 7cm and then another triangle whose sides are 7 of the corresponding sides of the first triangle.
Ans:
Ans: (i) Construct a triangle ABC in which AB = 7cm BC = 6 cm and AC = 5cm .
(ii) Make any acute angle BAX below the base AB.
(iii|) Located seven points A3,A4,A5,A6,A7, on the ray AX such that AA1 = A1A2 = A1A2 = A2A3 = A3A4= A4A5 = A5A6 = A6A7
(iv) 4. Join B*A_{5}
(v) Through B’ parallel to BC which meets AC at C’ on being producedA B’C’ is the required triangle.
(vi) Through B’ parallel to BC which meets AC at C’ on being produced.4. construct an isosceles triangle whose base is 8 cm and altitude 4cm and then another triangle whose sides are times the corresponding ΔA B’C’ is the required triangle.sides of the isosceles triangle.
4. Construct an isosceles triangle whose base is 8 cm and altitude 4cm and then another triangle whose sides are times the corresponding 1 /2 /2 sides of the isosceles triangle.
Ans: Steps of constrictions:
(i) Take base AB = 8cm
(ii) Draw the perpendicular bisector of AB. Let it intersect AB at ‘M’
(iii) With Mas centre and radius=4cm, draw an arc which intersects the perpendicular bisector at ‘C’.
(iv) Join CA and CB.
(v) ABC is an isos- circles with CA = CB
(vi) Make any acute angle BAX below the side BC.
(vii) Locate three (greater of 2 and 3 in 1 that AA,A,A,A,A, 1 3 or)A,A,A, an ‘AXE’ such
(viii) Join A₂(2nd point smaller of 2 and 3 in and B.
(ix) Through A,, draw a line parallel to A,B meet AB is B’ on being.10.
(x) Through B’, draw a line parallel to BC which meets AC in C’ on being produced.
ΔАВС is the required triangle whose sides are ing sides of ΔAAВС. 2 times the correspond-
5. Draw a triangle ABC with side BC = 6 cm, AB = 5cm and ∠ABC = 3 60°. Then construct a triangle whose sides are 4 of the corresponding sides of the triangle ABC.
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6. Let ABC be a right triangle in which AB = 6 cm. BC = 8cm and ∠B = 90°. BD is the perpendicular from B on AC. The circle though B, C, D is drawn. Construct the tangents from A to this circle.
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7. Draw a right triangle in which the sides (other than hypotenuse) are of length 4 cm and 3cm. Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle.
Ans:
| Exercise 11.2 |
1. Draw a circle of radius 6cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.
Ans: Steps of constructions:
2. Construct a tangent to a circle of radius 4cm from a point on the concentric circle of radius 6cm and measure its length. Also verify the measurement by actual calculation.
Ans: Steps of constructions:
3. Draw a circle of radius 3cm. Take two points P and Q on one of its extended diameters each at a distance of 7 cm from its centre. Draw tan- gents to the circle from these two points P and Q.
Ans:
4.Draw a pair of tangents to a circle of radius 5cm which are inclined to each other an angle of 60°.
Ans: steps of constructions:
5. Draw a line segment AB of length 8cm. Taking A as centre, draw a circle
of radius 4cm and taking B as centre, draw another circle of radius of 3 cm.Construct tangents to each circle from the centre of
6. Let ABC be a right triangle in which AB = 6 cm. BC = 8cm and ∠B = 90°. BD is the perpendicular from B on AC. The circle though B, C, D is drawn. Construct the tangents from A to this circle.
Ans: Steps of construction :
1. Construct a right angled triangle ABC accord- ing to given conditions and measurements.
2. Draw BDLAC.
3. Take midpoint of side BC take it as ‘M’.
4. Take ‘M’ as centre and BC as diameter, draw a circle through B, C, D during property, angle in semicircle is 90°. (∠BDC = 90°) Take this circle as I.
5. Now join ‘A’ and ‘M’. 6. Draw the perpendicular bisector of ‘N’. Now with ‘N’ as centre and ‘NA’
or ‘NM’ as radius, draw a circle (II) which intersects the circle (I) at ‘B’ and ‘P’.
7. Join AP.
8. AP and AB are the required tangents.
7. Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pair of tangents from this point to the circle.
Ans: Do yourself.
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