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Class 10 Computer Science Chapter 4 Introduction To Loops
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INTRODUCTION TO LOOPS
Chapter – 4
COMPUTER SCIENCE
TEXTUAL QUESTIONS AND ANSWERS
1. Why do we use a loop in a C program?
Ans. Looping can be defined as repeating the same process multiple times until a specific condition is satisfied.
1) It provides code reusability.
2) Using loops, we do not need to write the same code again and again.
3) Using loops, we can traverse over the elements of data structures (array or linked lists).
2. Do we need to use only one type of loop in a C program? Justify your answer by writing a C program.
Ans. No, in C programming, you are not limited to using just one type of loop. Depending on the specific requirements of a program, you can choose between different loop types, including –
- for loop.
- do…while loop.
- while loop.
Example:
Printing 5 times using all three types of loop.
#include <stdio.h>
int main() {
int i;
printf("Using a for loop to print numbers from 1 to 5:\n");
for (i = 1; i <= 5; i++) {
printf("%d ", i);
}
printf("\n");
printf("Using a while loop to print numbers from 6 to 10:\n");
i = 6;
while (i <= 10) {
printf("%d ", i);
i++;
}
printf("\n");
printf("Using a do-while loop to print numbers from 11 to 15:\n");
i = 11;
do {
printf("%d ", i);
i++;
} while (i <= 15);
printf("\n");
return 0;
}OUTPUT
Using a for loop to print numbers from 1 to 5:
1 2 3 4 5
Using a while loop to print numbers from 6 to 10:
6 7 8 9 10
Using a do-while loop to print numbers from 11 to 15:
11 12 13 14 15(3) What will happen if we write a while loop with 1 in place of condition? Try it in a simple C program.
Ans. If you write a ‘while’ loop with ‘1’ as the condition, the loop will run indefinitely because ‘1’ is always true in C programming. This creates an infinite loop, and the program will not terminate on its own.
To come out from this infinite loop, we have to use conditional statement and break statement.
Example:
#include <stdio.h>
int main() {
while (1) {
printf("This is an infinite loop.\n");
}
return 0;
}Explanation:
If you run this program, it will continuously print “This is an infinite loop” to the console, and there will be no end unless you manually terminate the program.
4. Name different portions of a for loop. Can we put more than one statement within a portion?
Ans. The three portions of the for loop are —
● Initialization expression.
● Condition/test expression.
● Update expression.
5. Answer with TRUE or False.
(1) If the condition of the while loop is false, the control comes to the second statement inside the loop.
Ans. FALSE.
(2) We can use at most three loops in a single C program.
Ans. FALSE.
(3) The statement inside the do-while loop executes when the condition is false.
Ans. FALSE.
(4) Only the first statement inside the do-while loop executes when the condition is false.
Ans. TRUE.
(5) In a do-while loop, the condition is written at the end of the loop.
Ans. TRUE.
6. Programming exercises:
A. Write the C program to find the summation of the following series.
(a) 1² + 2² + 3² + 4² + …..+ N²
Solution: Code:
#include <stdio.h>
int main() {
int N, sum = 0;
printf("Enter a positive integer N: ");
scanf("%d", &N);
for (int i = 1; i <= N; i++) {
sum += i * i;
}
printf("The sum of squares from 1² to %d² is: %d\n", N, sum);
return 0;
}Output:
Enter a positive integer N: 5
The sum of squares from 1² to 5² is: 55(b) 1³ + 2³ + 3³ + 4³ + …..+ N³
Solution:
Code:
#include <stdio.h>
int main() {
int i, N, sum = 0;
printf("Enter the value of N: ");
scanf("%d", &N);
for (i = 1; i <= N; i++) {
int cube = i * i * i;
sum = sum + cube;
}
printf("\nThe summation of cubes is %d\n", sum);
return 0;
}Output:
Enter the value of N: 4
The summation of cubes is 100(c) 1*2 + 2*3+ 3*4 + ……+ N*(N+1)
Solution: Code:
#include <stdio.h>
int main() {
int N, sum = 0;
printf("Enter a positive integer N: ");
scanf("%d", &N);
for (int i = 1; i <= N; i++) {
sum += i * (i + 1);
}
printf("The sum of products is: %d\n", sum);
return 0;
}Output:
Enter a positive integer N: 5
The sum of products is: 55B. Write a C program to continuously take a number as input and announce whether the number is odd or even.
Solution: Code:
#include <stdio.h>
int main() {
int num;
while (1) { // Infinite loop
printf("Enter a number (0 to exit): ");
scanf("%d", &num);
if (num == 0) {
printf("Exiting the program. Goodbye!\n");
break; // Exit the loop if 0 is entered
}
if (num % 2 == 0) {
printf("%d is an even number.\n", num);
} else {
printf("%d is an odd number.\n", num);
}
}
return 0;
}Output:
Enter a number (0 to exit): 7
7 is an odd number.
Enter a number (0 to exit): 12
12 is an even number.
Enter a number (0 to exit): 0
Exiting the program. Goodbye!C. Write the C program to display the following pattern.
1
1 1
1 1 1
1 1 1 1
1 1 1 1 1
Solution: Code:
#include <stdio.h>
int main() {
int rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 1; j <= i; j++) {
printf("1 ");
}
printf("\n");
}
return 0;
}Output:
Enter the number of rows: 5
1
1 1
1 1 1
1 1 1 1
1 1 1 1 1D. Write the C program to display the following pattern.
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1
Solution: Code:
#include <stdio.h>
int main() {
int rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 5; j >= 6 - i; j--) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}Output:
Enter the number of rows: 5
5
5 4
5 4 3
5 4 3 2
5 4 3 2 1E. Write the C program to display the following pattern.
5 4 3 2 1
5 4 3 2
5 4 3
5 4
5
Solution: Code:
#include <stdio.h>
int main() {
int rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) {
for (int j = 5; j >= i; j--) {
printf("%d ", j);
}
printf("\n");
}
return 0;
}Output:
Enter the number of rows: 5
5 4 3 2 1
5 4 3 2
5 4 3
5 4
5
Kindly correct the true and false statements.
Most of them are wrongly answered otherwise everything else is quite helpful.