NIOS Class 12 Chemistry Chapter 19 p-block Elements and their Compounds – I

NIOS Class 12 Chemistry Chapter 19 p-block Elements and their Compounds – I Solutions English Medium As Per New Syllabus to each chapter is provided in the list so that you can easily browse throughout different chapters NIOS Class 12 Chemistry Chapter 19 p-block Elements and their Compounds – I Notes in English and select need one. NIOS Class 12 Chemistry Solutions English Medium Download PDF. NIOS Study Material of Class 12 Chemistry Notes Paper Code: 313.

NIOS Class 12 Chemistry Chapter 19 p-block Elements and their Compounds – I

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Also, you can read the NIOS book online in these sections Solutions by Expert Teachers as per National Institute of Open Schooling (NIOS) Book guidelines. These solutions are part of NIOS All Subject Solutions. Here we have given NIOS Class 12 Chemistry Notes, NIOS Senior Secondary Course Chemistry Solutions in English for All Chapter, You can practice these here.

Chapter: 19

Module – VI: Chemistry of Elements

INTEXT QUESTIONS 19.1

1. Write the formula of the following:

(i) Boric acid.

(ii) Borax.

Ans: (i) B(OH)₃

(ii) Na₂B₄O₇.10H₂O

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2. Write one reaction for the preparation of diborane.

Ans: 4BCl₃ + 3LiAlH₄ → 2B₂H₆ + 3AlCl₃ + 3LiCl.

3. What is the general formula of alums?

Ans: NM(SO₄)₂ .12H₂O

Where N = monovalent large cation like K⁺ or NH⁴⁺ and M = trivalent cation like Al³⁺, Fe³⁺, Cr³⁺

4. Write the formula of anhydrous solid aluminium trichloride and its structure.

Ans: Al₂Cl₆.

5. Mention one use each of:

(i) borax.

(ii) boric acid.

(iii) boron trifluoride.

Ans: (i) as a flux, for glazing pottery and tiles : in the manufacture of optical and borosilicate glasses.

(ii) as an antiseptic, as a food preservative, for making enamels.

(iii) as a catalyst in Friedel-Crafts reaction.

6. Why aluminium become non-reactive after reacting with HNO₃.

Ans: Monoprotonic.

7. Orthoboric acid is monoprotonic or triprotonic.

Ans: Due to the formation of oxide layer

INTEXT QUESTIONS 19.2

1. Write two properties of diamond which are not exhibited by graphite.

Ans: Hardness and conducting nature. Diamond : hard, non conducting; graphite: soft, conducting.

2. What is the state of hybridization of carbon in (i) diamond (ii) graphite?

Ans: sp³ in diamond and sp² in graphite.

3. What is the nature of bond in carborundum?

Ans: Covalent

4. Write the state of hybridization of carbon in CCl₄.

Ans: sp3

5. Which one is affected by water and why; CCl₄ or SiCl₄?

Ans: SiCl₄, as silicon can accept electron pair in its d-orbitals from water molecule.

6. Which is an acidic oxide, CO or CO₂?

Ans: CO₂

7. What happens when SiO₂ is attacked by F₂?

Ans:. SiO₂ + 2F₂ → SiF₄ + O₂

INTEXT QUESTIONS 19.3

1. Does ‘NH₄OH’ exist as a molecule?

Ans: No. Nitrogen cannot increase its covalency beyond 4.

2. What is the bond angle in NH³ molecule?

Ans: 107⁰

3. What is the state of hybridization of N in NH₃?

Ans: sp³

4. Draw the structure of pyrophosphoric acid.

Ans: 

5. What happen when PCl3 is treated with water?

Ans: PCl₃ + 3H₂O ⎯→ H₃PO₃ + 3HCl

TERMINAL EXERCISE

1. Why is boric acid not a protonic acid?

Ans: Boric acid (H₃BO₃) is not a protonic acid because it doesn’t release H⁺ ions directly. Instead, it accepts OH⁻ ions from water, forming B(OH)₄⁻ and releasing H⁺ indirectly through water’s reaction.

B(OH)₃ + 2H₂O → B(OH)₄⁻ + H₃O⁺

This behavior classifies boric acid as a Lewis acid rather than a traditional protonic acid (Bronsted-Lowry acid).

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