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NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point

NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point Solutions English Medium As Per CBSE New Syllabus to each chapter is provided in the list so that you can easily browse through different chapters NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point Question Answer and select need one. NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point Notes Download PDF. CBSE Class 7 Solutions for Maths in English.

NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point

Also, you can read the NCERT book online in these sections Solutions by Expert Teachers as per Central Board of Secondary Education (CBSE) Book guidelines. NCERT Class 7 Mathematics Chapter 3 A Peek Beyond the Point Textual Solutions are part of All Subject Solutions. Here we have given CBSE Class 7 Maths Textbook Solutions English Medium for All Chapters, You can practice these here.

Chapter: 3

3.1 The Need for Smaller Units

Questions (Page No: 46-48)

1. In the following figure, screws are placed above a scale. Measure them and write their length in the space provided.

Ans: 

2. Which scale helped you measure the length of the screws accurately? Why?

Ans: The third scale helped us to measure the length of the screws accurately because each unit length has been further divided into 10 equal parts.

3. Can you explain why the unit was divided into smaller parts to measure the screws?

Ans: Yes, as the screws are so long that cannot be measured in exact unit length. Therefore, the unit was divided into smaller parts.

4. Measure the following objects using a scale and write their measurements in centimetres (as shown earlier for the lengths of the screws): pen, sharpener, and any other object of your choice.

Ans: Do it yourself.

5. Write the measurements of the objects shown in the picture:

Ans: Length of the eraser is 2 4/10 cm

Length of the pencil is 4 5/10 cm

Length of the chalk is 1 4/10 cm

3.2 A Tenth Part

(Page No: 49-52)

1. For the objects shown below, write their lengths in two ways and read them aloud. An example is given for the USB cable. (Note that the unit length used in each diagram is not the same.)

The length of the USB cable is 4 and 8/10 units or 48/10 units.

Ans: The length of the little finger is 1 and 3/10 units or 13/10 units;

The height of the geometry box is 2 and 8/10 units or 28/10 units;

and the length of a leaf is 10 and 9/10 units or 109/10 units.

2. Arrange these lengths in increasing order:

(a) 9/10

Ans: 9/10 → nine-tenths

(b) 1 7/10

Ans: 1 7/10 = 17/10 → one and seven-tenths or seventeen tenth

(c) 130/10

Ans: 130/10 → one hundred thirty-tenths

(d) 13 1/10

Ans: 13 1/10 = 131/10 → Thirteen and one-tenths or one hundred thirty-one tenths

(e) 10 5/10

Ans: 10 5/10 = 105/10 → Ten and five-tenths or one hundred five tenths

(f) 7 6/10

Ans: 7 6/10 = 76/10 → Seven and six-tenths or seventh-six tenths

(g) 6 7/10

Ans: 6 7/10 = 67/10 → Six and seven-tenths or sixty-seven tenths

(h) 4/10

Ans: 4/10  → four-tenths

These fractional units are in increasing order as:

4/10 < 9/10 < 1 7/10 < 6 7/10 < 7 6/10 < 10 5/10 < 130/10 <13 1/10

3. Arrange the following lengths in increasing order:

4 1/10, 4/10, 41/10, 41 1/10

Ans: We can see that 4 1/10 = 41/10 and 41 1/10 = 411/10

Therefore, the given lengths can be arranged in increasing order as:

4/10 < 4 1/10 = 41/10 < 41 1/10

4. The lengths of the body parts of a honeybee are given. Find its total length.

Head: 2 3/10 units

Thorax: 5 4/10 units

Abdomen: 7 5/10 units

Ans: The total length of a honeybee = length of the head + length of the thorax + length of the abdomen

5. A Celestial Pearl Danio’s length is 2 4/10 cm, and the length of a Philippine Goby is 9/10 cm. What is the difference in their lengths?

Ans: The length of a Celestial Pearl Danio fish = 2 4/10 cm = 24/10 cm

The length of a Philippine Goby fish = 9/10 cm

So, the difference in their lengths = 24/10 cm – 9/10 cm

= 15/10 cm

= 1 5/10 cm

6. How big are these fish compared to your figure?

Ans: Do it yourself.

7. Observe the given sequences of numbers. Identify the change after each term and extend the pattern:

(a) 4, 4 3/10, 4 6/10, _________, _________, _________, _________

Ans: 

(b) 8 2/10, 8 7/10, 9 2/10, _________, _________, _________, _________

Ans: 

(c) 7 6/10, 8 7/10, _________, _________, _________, _________

Ans: 

(d) 5 7/10, 5 3/10, _________, _________, _________, _________

Ans: 

(e) 13 5/10,13, 12 5/10, _________, _________, _________, _________

Ans: 

(f) 11 5/10,10 4/10, 9 3/10 ,  _________, _________, _________, _________

Ans: 

3.3 A Hundredth Part

(Pages No: 53-56)

1. What is the length of this smaller part? How many such smaller parts make a unit length?

Ans: Length of each smaller part on splitting each one-tenth into 10 parts = 1/100

100 such smaller parts make a unit length.

2. How many one-hundredths make one-tenth? Can we also say that the length is 4 units and 45 one-hundredths? (Length is 4 units and 4 one-tenths and 5 one-hundredths)

Ans: Number of one-hundredths in one-tenth = 1/100 + 1/10 = 10

4 units and 4 one-tenths and 5 one-hundredths = 4 + 4/10 + 5/100 = 4 + 0.4 + 0.45 = 4.45 units. 

4 units and 45 one-hundredths = 4 + 45/100 = 4 + 0.45 = 4.45 units.

Hence, 4 units and 4 one-tenths and 5 one-hundredths can also be written as 4 units and 45 one-hundredths.

3. Observe the figure below. Notice the markings and the corresponding lengths written in the boxes when measured from 0. Fill in the lengths in the empty boxes.

Ans: 

4. For the lengths shown below, write the measurements and read out the measures in words.

Ans: 

5. In each group, identify the longest and the shortest lengths. Mark each length on the scale.

Ans: 

Ans: 

Ans:

Ans: 

Ans: 

Ans: 

Ans: 

Figure it Out (Page No: 58)

1. Find the sums and differences:

(a) 3/10 + 3 4/100

Ans:

(b) 9 5/10 7/100 + 2 1/10 3/100

Ans: 

(c) 15 6/10 4/100 + 14 3/10 6/100

Ans: 

(d) 7 7/100 − 4 4/100

Ans: 

(e) 8 6/100 − 5 3/100

Ans: 

(f) 12 6/100 2/100 − 9/10 9/100

Ans: 

3.4 Decimal Place Value

(Page No: 61-64)

1. We can ask similar questions about fractional parts:

(a) How many thousandths make one unit?

(b) How many thousandths make one tenth?

(c) How many thousandths make one hundredth?

(d) How many tenths make one ten?

(e) How many hundredths make one ten?

Ans: We know that the value of a place in the decimal place value chart becomes ten times at every step moving from right to left, and it becomes [Math Processing Error] times moving from left to right.

Therefore,

TensOnesTenthsHundredthsThousandths
1011/101/1001/1000

2. Make a few more questions of this kind and answer them.

Ans: Do it yourself.

3. Make a place value table similar to the one above. Write each quantity in decimal form and terms of place value, and read the number:

(a) 2 ones, 3 tenths, and 5 hundredths

(b) 1 ten and 5 tenths

(c) 4 ones and 6 hundredths

(d) 1 hundred, 1 one, and 1 hundredth

(e) 8/100 and 9/10

(f) 5/100

(g) 1/10

(h) 2 1/100, 4 1/10 and 7 7/1000

Ans: 

4. Write these quantities in decimal form:

(a) 234 hundredths

Ans: 234 hundredths can be expressed in decimal form as follows:

234 hundredths = 234/100 = 200/100 + 30/100 + 4/100

= 2 + 3/10 + 4/100

= 2.34

HundredsTensOnesDecimal pointTenthsHundredths
234
234

(b) 105 tenths.

Ans: 105 tenths can be expressed in decimal form as follows:

105 tenths = 105/10

= 100/10 + 0/10 + 5/10

= 10 + 0 + 5/10

= 10.5

HundredsTensOnesDecimal pointTenthsHundredths
105
10
3.5 Units of Measurement

(Page No: 65-66)

Length Conversion

1. Fill in the blanks below (mm <-> cm)

12 mm = 1.2 cm56 mm = 5.6 cm70 mm = _______
______ = 0.9 cm134 mm = _____________ = 203.6 cm

Ans: 

12 mm = 1.2 cm56 mm = 5.6 cm70 mm = _______
9 mm = 0.9 cm134 mm = 1.34 cm2036 mm = 203.6 cm

2. Fill in the blanks below (cm <-> m)

36 cm = _______50 cm = ______________ = 0.89 m
4 cm = _______325 cm = _______________ = 2.07 m

Ans: 

36 cm = 0.36 cm50 cm = 0.5 m89 cm = 0.89 m
4 cm = 0.04 m325 cm = 3.25 m207 cm = 2.07 m

3. How many mm does 1 m have?

Ans: 1000 mm = 1 m

[As, 1 m = 100 cm = 100 × 10 mm]

(Page No: 67-68)

Weight Conversion

1. Fill in the blanks below (g <-> kg)

465 g = ______68 g = _________ 1560 g = ________
704 g = _______________ = 0.56 kg_______ = 2.5 kg

Ans: 

465 g = 0.465 kg68 g = 0.068 kg1560 g = 1.56 kg
704 g = 0.704 kg560 g = 0.56 kg2500 = 2.5 kg

(Page No: 69)

Rupee-Paise Conversion

1. Fill in the blanks below (rupee ↔ paise)

10 p = __________________p = ₹ 0.05________p = ₹ 0.36
_________ = ₹ 0.5099 p = _________250 p = _________

Ans: 

10 p = ₹ 0.15 p = ₹ 0.0536 p = ₹ 0.36
50 p  = ₹ 0.5099 p = ₹ 0.99250 p = ₹ 2. 50
3.6 Locating and Comparing Decimals

(Page No: 70)

1. Name all the divisions between 1 and 1.1 on the number line.

Ans: The divisions between 1 and 1.1 represent the decimal numbers 1.01, 1.02, 1.03, 1.04, 1.05, 1.06, 1.07, 1.08, and 1.09 on the number line.

2. Identify and write the decimal numbers against the letters.

Ans: The letters marked on the given number line represent the decimal numbers as follows:

A → 5.09, B → 5.13, C → 5.2, D → 5.31

There is Zero Dilemma!

(Page No: 71-73)

1. Can you tell which of these (0.2, 0.02, and 0.002) is the smallest and which is the largest?

Ans: From the decimal place value chart, we see that

OnesDecimal PointTenthsHundredthsThousandths
0.2
0.02
0.002

0.002 representing 2 thousandths is the smallest, and 0.2 representing 2 tenths is the largest decimal number among the given decimals.

2. Which of these are the same: 4.5, 4.05, 0.405, 4.050, 4.50, 4.005, 04.50?

Ans: From the decimal place value chart, we see that

TensOnesDecimal PointTenthsHundredthsThousandths
4.5
4.05
0.405
4.050
4.50
4.005
04.50

4.5, 4.50, and 04.50 are equal as they represent the same quantity, i.e., four ones and five tenths.

Similarly, 4.05 and 4.050 are equal as they represent the same quantity, i.e., four ones and five hundredths.

But, 0.405 and 4.005 are different as they do not represent the same quantity.

3. Identify the decimal number in the last number line in Figure (b) denoted by‘?’

Ans: 

By labelling the visualised segment of the number line, we find that the decimal number 3.059 is denoted by ‘?’

4. Make such number lines for the decimal number:

(a) 9.876

Ans: 

(b) 0.407

Ans: 

5. In the number line shown below, what decimal numbers do the boxes labelled ‘a’, ‘b’, and ‘c’ denote?

The box with ‘b’ corresponds to the decimal number 7.5; are you able to see how? There are 5 units between 5 and 10, divided into 10 equal parts. Hence, every 2 divisions make a unit, and so every division is 1/2 unit. What numbers do ‘a’ and ‘c’ denote?

Ans: Since each division between 5 and 10 is1/2 = 0.5 unit.

Therefore, the second division after 5, denoted by ‘a’, represents the number 6, while the ninth division, denoted by ‘c’, represents the decimal number 9.5.

6. Using similar reasoning, find out the decimal numbers in the boxes below.

Ans: There are 10 divisions between 8 and 8.1, so each division is a tenth part of 1/2, i.e., 1/100 = 0.01 unit.

Therefore, the first division after 8, denoted by ‘d’ represents the decimal number 8.01, while the fifth division, denoted by ‘e’, represents the decimal number 8.05.

Further, there are 10 divisions between 4.3 and 4.8, so each division is a tenth part of 0.5 or 5/10, i.e., 5/100 = 0.05 unit.

Therefore, the first division after 4.3, denoted by ‘f’, represents the decimal number 4.35, while the fourth division, denoted by ‘g’, represents the decimal number 4.5, and the first division after 4.8, denoted by ‘h’, represents the decimal number 4.85.

7. Which decimal number is greater?

(a) 1.23 or 1.32

Ans: Using the decimal place value chart, we find that:

TensOnesDecimal pointTenthsHundredthsThousandths
1.23
1.32

Both numbers have 1 unit, but the first number has 2 tenths, whereas the second number has 3 tenths.

Therefore, 1.23 < 1.32.

(b) 3.81 or 13.800

Ans: Using the decimal place value chart, we find that:

TensOnesDecimal pointTenthsHundredthsThousandths
3.81
13.800

Here, the first number has 3 units, whereas the second number has 1 ten and 3 units.

Therefore, 3.81 < 13.800.

(c) 1.009 or 1.090

Ans: Using the decimal place value chart, we find that:

TensOnesDecimal pointTenthsHundredthsThousandths
1.009
1.090

Both numbers have 1 unit and 0 tenths, but the first number has 0 hundredths, whereas the second number has 9 hundredths.

Therefore, 1.009 < 1.090.

(Page No:73)

Closest Decimals

1. Which of the decimal numbers 0.9, 1.1, 1.01, and 1.11 is closest to 1.09?

Ans: Arranging the decimal numbers in ascending order, we have 0.9 < 1.01 < 1.09 < 1.1 < 1.11

Among the neighbours of 1.09, 1.01 is 8/100 away from 1.09, whereas 1.1 is 1/100 away from 1.09. 

Therefore, 1.1 is closest to 1.09.

2. Which among these is closest to 4: 3.56, 3.65, 3.099?

Ans: Arranging the decimal numbers in ascending order, we have 3.099 < 3.56 < 3.65 < 4 3.65 is closest to 4 among the given decimal numbers.

3. Which among these is closest to 1: 0.8, 0.69, 1.08?

Ans: Arranging the decimal numbers in ascending order, we have 0.69 < 0.8 < 1 < 1.08

Among the neighbours of 1, 0.8 is 2/10, i.e., 20/100 away from 1 whereas 1.08 is 8/100 away from 1.

Therefore, 1.08 is closest to 1.

4. In each case below, use the digits 4, 1, 8, 2, and 5 exactly once and try to make a decimal number as close as possible to 25.

Ans: We can make a decimal number closest to 25 using the digits 4, 1, 8, 2, and 5 with the given conditions as follows:

3.7 Addition and Subtraction of Decimals

(Page No: 75)

1. Write the detailed place value computation for 84.691 – 77.345, and its compact form.

Ans: We can find the difference of 84.691 – 77.345 as follows:

Figure it Out (Page No: 75)

1. Find the sums.

(a) 5.3 + 2.6

(b) 18 + 8.8

(c) 2.15 + 5.26

(d) 9.01 + 9.10

(e) 29.19 + 9.91

(f) 0.934 + 0.6

(g) 0.75 + 0.03

(h) 6.236 + 0.487

Ans: 

2. Find the differences.

(a) 5.6 – 2.3

(b) 18 – 8.8

(c) 10.4 – 4.5

(d) 17 – 16.198

(e) 17 – 0.05

(f) 34.505 – 18.1

(g) 9.9 – 9.09

(h) 6.236 – 0.487

Ans: 

(Page No: 75-76)

Decimal Sequences

1. Observe this sequence of decimal numbers and identify the change after each term.

4.4, 4.8. 5.2, 5.6, 6.0,….

We can see that 0.4 is being added to a term to get the next term.

Continue this sequence and write the next 3 terms.

Ans: 4.4, 4.8. 5.2, 5.6, 6.0, 6.4, 6.8, 7.2

2. Similarly, identify the change and write the next 3 terms for each sequence given below. Try to do this computation mentally.

(a) 4.4, 4.45, 4.5,..…

(b) 25.75, 26.25, 26.75,……

(c) 10.56, 10.67, 10.78,….…

(d) 13.5, 16, 18.5,….…

(e) 8.5, 9.4, 10.3,……

(f) 5, 4.95, 4.90,……

(g) 12.45, 11.95, 11.45,……

(h) 36.5, 33, 29.5,……

Ans: 

3. Make your sequences and challenge your classmates to extend the pattern.

Ans: Do it yourself.

(Page No: 76)

Estimating Sums and Differences

1. Sonu has observed sums and differences of decimal numbers and says, “If we add two decimal numbers, then the sum will always be greater than the sum of their whole number parts. Also, the sum will always be less than 2 more than the sum of their whole number parts.”

Let us use an example to understand what his claim means:

If the two numbers to be added are 25.936 and 8.202, the claim is that their sum will be greater than 25+ 8 (whole number parts) and will be less than 25 + 1 + 8 + 1.

What do you think about this claim? Verily if this is true for these numbers. Will it work for any 2 decimal numbers?

Ans: The given numbers are 25.936 and 8.202.

Sum of whole number parts = 25 + 8 = 33

Sum of given decimal numbers = 25.936 + 8.202 = 34.138

Clearly, 33 < 34.138 < (33 + 2)

Let another two decimal numbers 1.532 and 4.536

Sum of whole number part = 1 + 4 = 5

Sum of given decimal numbers = 1.532 + 4.536 = 6.068

Clearly, 5 < 6.068 < 5 + 2

So, the claim is true for the sum of any two decimal numbers.

2. What about for the sum of 25.93603259 and 8.202?

Ans: The given numbers are 25.93603259 and 8.202.

Sum of whole number parts = 25 + 8 = 33

Sum of given decimal numbers = 25.93603259 + 8.202 = 34.13803259

Clearly, 33 < 34.13803259 < (33 + 2)

3. Similarly, come up with a way to narrow down the range of whole numbers within which the difference of two decimal numbers will lie.

Ans: If we subtract two decimal numbers, then the difference will always be smaller than the difference of their whole number parts +1.

Also, the difference will always be greater than the difference of their whole-number parts minus 1.

Verify it yourself.

3.8 More on the Decimal

Figure it Out (Page No: 78-80)

1. Convert the following fractions into decimals:

(a) 5/100

(b) 16/1000

(c) 12/10

(d) 254/1000

Ans: 

2. Convert the following decimals into a sum of tenths, hundredths, and thousandths:

(а) 0.34

(b) 1.02

(c) 0.8

(d) 0.362

Ans: 

3. What decimal number does each letter represent in the number line below?

Ans: There are 4 divisions between 6.4 and 6.5, so each division is one-fourth part of 0.1 or 1/10, i.e., 1/40 = 0.025 units.

Therefore, the second division after 6.4, denoted by ‘a’, represents the number 6.45, while the first division after 6.5, denoted by ‘c’, represents the number 6.525, and the second division after 6.5, denoted by ‘b’, represents the number 6.55.

4. Arrange the following quantities in descending order:

(a) 11.01, 1.011, 1.101, 11.10, 1.01

Ans: Using the decimal place value chart, we find that:

TensOnesDecimal pointTenthsHundredthsThousandths
11.01
1.011
1.101
11.10
1.01

Here, the two numbers 11.01 and 11.10 have 11 whole-number parts, but the first number has 0 tenths, whereas the second number has 1 tenth. Therefore, 11.10 > 11.01. The three numbers 1.011, 1.101, and 1.01 have 1 whole number part, but the first and third numbers have 0 tenths, whereas the second number has 1 tenth. Therefore, 1.101 is the greatest among the three. Now, comparing the remaining two numbers, we get 1.011 > 1.01.

Thus, the numbers in descending order are: 11.10 > 11.01 > 1.101 > 1.011 > 1.01.

(b) 2.567, 2.675, 2.768, 2.499, 2.698

Ans: 2.567, 2.675, 2.768, 2.499, 2.698

TensOnesDecimal pointTenthsHundredthsThousandths
2.567
2.675
2.768
2.499
2.698

Thus, the given quantities in descending order are:

2.768 > 2.698 > 2.675 > 2.567 > 2.499

(c) 4.678 g, 4.595 g, 4.600 g, 4.656 g, 4.666 g

Ans: 4.678 g, 4.595 g, 4.600 g, 4.656 g, 4.666 g

TensOnesDecimal pointTenthsHundredthsThousandths
4.678
4.595
4.600
4.659
4.668

Thus, the given quantities in descending order are:

4.678 g > 4.666 g > 4.656 g > 4.600 g > 4.595 g.

(d) 33.13 m, 33.31 m, 33.133 m, 33.331 m, 33.313 m

Ans: 33.13 m, 33.31 m, 33.133 m, 33.331 m, 33.313 m

TensOnesDecimal pointTenthsHundredthsThousandths
33.13
33.31
33.133
33.331
33.313

Thus, the given quantities in descending order are:

33.331 m > 33.313 m> 33.31 m > 33.133 m > 33.13 m.

5. Using the digits 1, 4, 0, 8, and 6, make:

(a) The decimal number closest to 30.

(b) The smallest possible decimal number between 100 and 1000.

Ans: Using the digits 1, 4, 0, 8, and 6, we can make:

(a) The decimal number closest to 30 → 40.168.

(b) The smallest possible decimal number between 100 and 1000 → 104.68

6. Will a decimal number with more digits be greater than a decimal number with fewer digits?

Ans: No. It is not necessary as 0.9 > 0.123456789.

7. Mahi purchases 0.25 kg of beans, 0.3 kg of carrots,0.5 kg of potatoes, 0.2 kg of capsicums, and 0.05 kg of ginger. Calculate the total weight of the items she bought.

Ans: The total weight of the items Mahi bought = 0.25 kg + 0.3 kg + 0.5 kg + 0.2 kg + 0.05 kg = 1.3 kg.

8. Pinto supplies 3.79 L, 4.2 L, and 4.25 L of milk to a milk dairy in the first three days. In 6 days, he supplies 25 litres of milk. Find the total quantity of milk supplied to the dairy in the last three days.

Ans: The total quantity of milk supplied to the dairy in the last three days = Total milk supplied in the 6 days – Total milk supplied in the first 3 days

= 25 L – (3.79 L + 4.2 L + 4.25 L)

= 25 L – 12.24 L

= 12.76 L

9. Tinku weighed 35.75 kg in January and 34.50 kg in February. Has he gained or lost weight? How much is the change?

Ans: Since 35.75 kg > 34.50 kg, Tinku has lost weight.

Now, the change in the weight = 35.75 kg – 34.50 kg = 1.25 kg.

10. Extend the pattern: 5.5, 6.4, 6.39, 7.29, 7.28, 8.18, 8.17, ____, _____

Ans: Let us analyse the given pattern:

5.5 (+0.9) 6.4 (-0.01) 6.39 (+0.9) 7.29 (-0.01) 7.28 (+0.9) 8.18 (-0.01) 8.17.

So, the sequence follows an increasing trend of 0.9 and then a decreasing trend of 0.01 alternatively.

Thus, the next two numbers are 9.07 and 9.06.

11. How many millimetres make 1 kilometre?

Ans: We know that 1 km = 1000 m and 1 m = 1000 mm

Therefore, 1 km = 1000 × 1000 mm= 1000000 mm

12. Indian Railways offers optional travel insurance for passengers who book e-tickets. It costs 45 paise per passenger. If 1 lakh people opt for insurance in a day, what is the total insurance fee paid?

Ans: The insurance fee paid for 1 passenger = 45 p = ₹ 0.45

So, total insurance fee paid for 1 lakh passengers = ₹ 0.45 × 100000 = ₹ 45000

13. Which is greater?

(a) 10/1000 or 1/10?

(b) One-hundredth or 90 thousandths?

(c) One-thousandth or 90 hundredths?

Ans: 

14. Write the decimal forms of the quantities mentioned (an example is given):

(a) 87 ones, 5 tenths, and 60 hundredths = 88.10

(b) 12 tens and 12 tenths

(c) 10 tens, 10 ones, 10 tenths, and 10 hundredths

(d) 25 tens, 25 ones, 25 tenths, and 25 hundredths

Ans: (a) 87 ones, 5 tenths, and 60 hundredths = 88.10

15. Using each digit 0-9 not more than once, fill the boxes below so that the sum is closest to 10.5:

Ans: 

16. Write the following fractions in decimal form:

(a) 1/2

(b) 3/2

(c) 1/4

(d) 3/4

(e) 1/5

(f) 4/5

Ans: 

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