Class 12 Chemistry MCQ Chapter 3 Electrochemistry

Class 12 Chemistry MCQ Chapter 3 Electrochemistry Solutions to each chapter is provided in the list so that you can easily browse through different chapters Class 12 Chemistry MCQ Chapter 3 Electrochemistry Question Answer and select need one. Class 12 Chemistry MCQ Chapter 3 Electrochemistry Guide Download PDF. AHSEC Chemistry Multiple Choice Class 12 Solutions.

Class 12 Chemistry MCQ Chapter 3 Electrochemistry

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Also, you can read the NCERT book online in these sections Solutions by Expert Teachers as per Central Board of Secondary Education (CBSE) Book guidelines. HS 2nd Year Chemistry Objective Type Solutions are part of All Subject Solutions. Here we have given NCERT Class 12 Chemistry Multiple Choice Question and Answer, NCERT Class 12 Chemistry Objective Type Solutions for All Chapters, You can practice these here.

Chapter: 3

MCQ

1. The correct order of equivalent conductance at infinite dilution of LiCl, NaCl and KCl:

(i) KCl > NaCl > LiCl.

(ii) LiCl > NaCl > KCL.

(iii) LiCl > KCL > NaCl.

(iv) NaCl > KCl > LiCl.

Ans: (i) KCl > NaCl > LiCl.

2. What happens when the external voltage exceeds 1.1 V in a Daniell cell? 

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(i) Current flows from Zn to Cu.

(ii) Electrons flow from Cu to Zn.

(iii) Zinc is deposited at the zinc electrode.

(iv) Both (ii) and (iii).

Ans: (iv) Both (ii) and (iii).

3. The atmospheric pollution is generally measured in the units of

(i) Mass percentage.

(ii) Volume percentage.

(iii) Volume fraction.

(iv) Ppm.

Ans: (iv) Ppm.

4. Which chemical reaction occurs in a Daniell cell? 

(i) Zn(s) + O₂(g) → ZnO(s)

(ii) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

(iii) Cu(s) + Ag⁺(aq) → Cu²⁺(aq) + Ag(s)

(iv) Na(s) + Cl₂(g) → NaCl(s)

Ans: (ii) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

5. In the Daniell cell reaction, which substance is oxidised?

(i) Cu²⁺

(ii) Zn

(iii) Cu

(iv) Zn²⁺

Ans: (ii) Zn

6. The standard electrode (reduction) potentials of elements A, B and Care + 0.68 V, -2.50 V and – 0.50 V respectively. The correct order of their reducing powers is:

(i) A > B > C

(ii) B > C > A

(iii) C > B > A

(iv) A > C > B

Ans: (i) A > B > C

7. NH4NC3 is used in salt bridge because

(i) It forms a jelly like material with agar-agar.

(ii) It is a weak electrolyte.

(iii) It is a good conductor of electricity.

(iv) The transport number of NH4+ and NO3 ions are almost equal.

Ans: (iv) the transport number of NH4+ and NO3 ions are almost equal.

8. Which half-reaction occurs at the cathode of a Daniell cell? 

(i) Zn(s) → Zn²⁺(aq) + 2e⁻.

(ii) Cu²⁺(aq) + 2e⁻ → Cu(s).

(iii) Cu(s) → Cu²⁺(aq) + 2e⁻.

(iv) Zn²⁺(aq) + 2e⁻ → Zn(s).

Ans: (ii) Cu²⁺(aq) + 2e⁻ → Cu(s).

9. The conductivity of molten NaCl is due to:

(i) Free ions.

(ii) Free electrons.

(iii) Free molecules.

(iv) Atoms of Na and Cl.

Ans: (i) Free ions.

10. The charge required for the reduction of 1 mol of MnO4 to MnO2 is

(i) 1 F.

(ii) 3 F.

(iii) 5 F.

(iv) 6 F.

Ans: (iii) 5 F.

11. Which of the following represents a galvanic cell configuration?

(i) Cu(s) || Zn²⁺(aq) | Zn(s).

(ii) Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s).

(iii) Zn²⁺(aq) || Cu²⁺(aq).

(iv) Cu(s) | Cu²⁺(aq) || Zn(s) | Zn²⁺(aq).

Ans: (ii) Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s).

12. Charge required to liberate 11.5 g sodium is:

(i) 0.5 F.

(ii) 1.5 F.

(iii) 0.1 F.

(iv) 0.05F.

Ans: (ii) 1.5 F.

13. For the half-cell reaction Zn²⁺(aq) + 2e⁻ → Zn(s), what is the value of the standard electrode potential? 

(i) 0.34 V.

(ii) +0.76 V.

(iii) -0.76 V.

(iv) +1.10 V.

Ans: (iii)-0.76 V.

14. If limiting molar conductivity of Ca2+ and Cl are 119.0 and 76.3 S cm2 mol-1, then the value of limiting molar conductivity of CaCl2 will be

(i) 195.3 S cm2 mol-1

(ii) 271.6 S cm2 mol-1

(iii) 43.3 S cm2 mol-1

(iv) 314.3 S cm2 mol-1

Ans: (ii) 271.6 S cm2 mol-1

15. What is the overall cell reaction for the Daniell cell involving zinc and copper?

(i) Zn²⁺(aq) + Cu(s) → Zn(s) + Cu²⁺(aq).

(ii) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s).

(iii) Cu²⁺(aq) + Zn(s) → Cu(s) + Zn²⁺(aq).

(iv) Cu(s) + Zn²⁺(aq) → Cu²⁺(aq) + Zn(s).

Ans: (ii) Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s).

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